EBook Problems Distrib MeanVar
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:''(d) 0.6275 | :''(d) 0.6275 | ||
{{hidden|Answer|(c)}} | {{hidden|Answer|(c)}} | ||
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| + | ===Problem 5=== | ||
| + | Defective Tires | ||
| + | The probability distribution of x, the number of defective tires on randomly selected automobiles at a certain inspection station, is given in the accompanying table: | ||
| + | |||
| + | {|border="1" | ||
| + | |- | ||
| + | | X = defective || 0 || 1 || 2 || 3 || 4 | ||
| + | |- | ||
| + | | Probability (X) || 0.54 || 0.16 || 0.06 || 0.04 || 0.20 | ||
| + | |} | ||
| + | |||
| + | |||
| + | After you calculate the expected number (the mean) of defective tires, determine the probability that x exceeds the expected value. | ||
| + | |||
| + | *Choose one answer. | ||
| + | |||
| + | :''(a) None of these values | ||
| + | |||
| + | :''(b) 0.54 | ||
| + | |||
| + | :''(c) 0.16 | ||
| + | |||
| + | :''(d) 0.30 | ||
| + | |||
| + | :''(e) 0.70 | ||
| + | {{hidden|Answer|(d)}} | ||
<hr> | <hr> | ||
Revision as of 05:48, 4 January 2009
Contents |
EBook Problems Set - Expectation (Mean) and Variance
Problem 1
Ming’s Seafood Shop stocks live lobsters. Ming pays $6.00 for each lobster and sells each one for $12.00. The demand X for these lobsters in a given day has the following probability mass function.
| X | 0 | 1 | 2 | 3 | 4 | 5 |
| P(x) | 0.05 | 0.15 | 0.30 | 0.20 | 0.20 | 0.1 |
What is the Expected Demand?
- Choose one answer.
- (a) 13.5
- (b) 3.1
- (c) 2.65
- (d) 5.2
Problem 2
If sampling distributions of sample means are examined for samples of size 1, 5, 10, 16 and 50, you will notice that as sample size increases, the shape of the sampling distribution appears more like that of the:
- Choose one answer.
- (a) normal distribution
- (b) uniform distribution
- (c) population distribution
- (d) binomial distribution
Problem 3
The number of flaws on an electroplated automobile grill is known to have following probability distribution:
| X | 0 | 1 | 2 | 3 |
| P(X) | 0.8 | 0.1 | 0.05 | 0.05 |
For a random sample of 200 grills, calculate the approximate probability that the average number of flaws per grill exceeds 0.4
- Choose one answer.
- (a) 0.0002
- (b) None of the above
- (c) 1
- (d) 0.1860 approximately
Problem 4
The number of flaws on an electroplated automobile grill is known to have following probability distribution:
| X | 0 | 1 | 2 | 3 |
| P(X) | 0.8 | 0.1 | 0.05 | 0.05 |
What would be the standard deviation of the sample means if we took 100 samples, each sample with 200 grills, and computed their sample means?
- Choose one answer.
- (a) None of the above
- (b) 0.89269
- (c) 0.0560
- (d) 0.6275
Problem 5
Defective Tires The probability distribution of x, the number of defective tires on randomly selected automobiles at a certain inspection station, is given in the accompanying table:
| X = defective | 0 | 1 | 2 | 3 | 4 |
| Probability (X) | 0.54 | 0.16 | 0.06 | 0.04 | 0.20 |
After you calculate the expected number (the mean) of defective tires, determine the probability that x exceeds the expected value.
- Choose one answer.
- (a) None of these values
- (b) 0.54
- (c) 0.16
- (d) 0.30
- (e) 0.70
- Back to Ebook
- SOCR Home page: http://www.socr.ucla.edu
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